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x=-2x^2+6.4x
We move all terms to the left:
x-(-2x^2+6.4x)=0
We get rid of parentheses
2x^2-6.4x+x=0
We add all the numbers together, and all the variables
2x^2-5.4x=0
a = 2; b = -5.4; c = 0;
Δ = b2-4ac
Δ = -5.42-4·2·0
Δ = 29.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.4)-\sqrt{29.16}}{2*2}=\frac{5.4-\sqrt{29.16}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.4)+\sqrt{29.16}}{2*2}=\frac{5.4+\sqrt{29.16}}{4} $
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